The goal of this lab is to practice using bit operations; in this case, we will use an ordered collection of bits to represent a dynamic set.
See the pre-lab reading to review the background information.
Make a new directory for this lab, and then copy the files found in the class directory for this project.
cp ~tvandrun/Public/cs245/lab8/* .
The file bitvector.h contains
the definition of the bit-vector type and the
prototype for the functions you have to write.
bitvector.c contains stubs, and vectest.c
runs a driver program.
The file makefile is a makefile to help you manage this
project.
Open bitvector.h and look at the
struct type BitVector_t.
Since we don't know how many bits we'll need,
we have a pointer called vector that
refers to the first byte of the memory area we'll
use.
size keeps track of the actual number of
bits (not bytes) we're using.
If we need to store 10 bits, we will allocate 2 bytes;
all eight bits of the first byte will be used (for bits 0-7),
and the first two bits of the second will be used (for bits 8 and 9);
the other bits of the second byte will simply be left unused.
The type of the vector pointer is unsigned char
*.
It will be easier to think of this as an array.
In bitvector.c, implement the function
createBitVector().
You'll need to allocate the struct object, as well
as allocating the vector (array) itself.
Think about how to determine the number of bytes you'll need
given the desired number of bits.
Also, make sure the set is initially empty.
At the same time, implement the destroy() function.
Just make sure you free everything that was allocated.
Compile bitvector.c and vectest.c
and test.
Right now vectest.c does not do very much, but test
that everything compiles and does not crash.
Now write contains().
This requires you to pick out the right byte offset from the
vector pointer (ie, get the
right unsigned char from the array), and then isolate the correct bit from
from that byte.
Uncomment the relevant section in vectest.c,
compile, and run.
The driver will print out the contents of the set.
Write insert().
Now you will need to modify one of the bits (in one of the bytes).
Think carefully about how to do this using bit operations.
Notice the driver requires a two-byte vector, and it inserts 5 and 9--thus,
one bit in the first byte and one bit in the second byte.
Uncomment, compile, and test.
By now, removing and element shouldn't be that bad.
(The function is called removeV() because
one of the libraries we include already had a remove()
function.)
One thing that sets apart the operations union, intersection, difference, and complement is that they do not modify their operand bit vectors, but rather create new ones. For each of these, you will have to allocate new bit vectors to represent the results.
We'll do complement first, since it needs only one operand.
Make a new bit vector to return (same size as the operand), and make all
its bits to be
the opposite of the bits in the operand.
For efficiency, don't do this one bit at a time.
Do it for each byte as a whole using C's bit-wise
negation operator, ~
In other words, loop through the bytes, setting
each byte in the new bit vector to be the bit-wise negation
of the equivalent byte in the old bit vector.
Don't worry that this will also affect the unused bits in the
last byte--- since they're unused, it won't do any harm to
negate them as well.
Notice that you had to calculate the number of bytes again,
based on the number of bits.
When you do something twice, it's a sign there should be a separate
function to calculate that.
Write a function numBytes() that takes a number
of bits and calculates the bytes required.
Replace that calculation in complement() and
createBitVector() with calls to that function.
Uncomment, compile, test.
Next, implement union.
This also can be done efficiently with a bitwise operator.
(Why is the method called unionV()?
Well, union is actually a reserved word in C.
I called this function unionV() for "vector".)
Uncomment, compile, test.
Are you getting the hang of this? Intersection should be easy now.
Finally, compute set difference.
Now let's use this in a real application. The Sieve of Eratosthenes is a method for finding prime numbers. One makes a list of integers from 2 up to some specified largest number. We will cross off numbers as we find them not to be prime. Initially assume all numbers are prime, which is true at least for the first number in the list, 2. Then, starting with 2, repeatedly
Thus in the first iteration, we'll cross off every even number; in the second iteration, we'll cross off every multiple of 3; etc.
Write a program that uses one of your bit vectors to keep track of the numbers in the sieve. Your program should